1。不均衡な方程式を書きます:
C₂H₆ + O₂ → CO₂ + H₂O
2。炭素原子のバランス:
There are 2 carbon atoms on the left side and 1 on the right. Place a coefficient of 2 in front of CO₂:
C₂H₆ + O₂ → 2CO₂ + H₂O
3。水素原子のバランス:
There are 6 hydrogen atoms on the left and 2 on the right. Place a coefficient of 3 in front of H₂O:
C₂H₆ + O₂ → 2CO₂ + 3H₂O
4。酸素原子のバランス:
There are 2 oxygen atoms on the left and 7 on the right. Place a coefficient of 7/2 in front of O₂:
C₂H₆ + 7/2 O₂ → 2CO₂ + 3H₂O
5。 (Optional) Make coefficients whole numbers:
Multiply the entire equation by 2 to get rid of the fraction:
2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O
バランスの取れた方程式はです
2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O